Question

find the remainder when x³+3x²+3x+1 is divided by x-1

Answer 1

Hey friend!
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Here is your answer
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p(x) = x^3 +3x^2 +3x +1

g(x) = x-1
x = 1

Thus,

p(1) = (1)^3 +3(1)^2 +3(1) +1

p(1) = 1 + (3×1) + 3 + 1

p(1) = 1 + 3 + 3 + 1

p(1) = 8

The remainder is 8
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HOPE THIS HELPS YOU :)

Answer 2

  x - 1 ) x³ + 3x² + 3x + 1 ( x² +  4x -7 
            x³ - x²
------------------------------
                4x² + 3x
                4x²  -4x 
-------------------------------------
                      7x + 1
                      7x - 7 
-----------------------------------------------
                             8
    
hence remainder is 8