what is the integral of tan inverse X upon 1 plus x square
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as you know
∫f(x)ⁿ.f'(x)dx = f(x)⁽ⁿ⁺¹⁾/(n + 1) + C
use this concept here ,
∫tan⁻¹x.{1/(1 + x²)}.dx = (tan⁻¹x)²/2 + C
∫f(x)ⁿ.f'(x)dx = f(x)⁽ⁿ⁺¹⁾/(n + 1) + C
use this concept here ,
∫tan⁻¹x.{1/(1 + x²)}.dx = (tan⁻¹x)²/2 + C
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