Question

find the remainder when x³+3x²+3x+1 is divided by:-x+π (by division method)

Answer 1

Answer:

Quotient=x²+(3-π)x+(3-3π+π²)

Quotient=x²+(3-π)x+(3-3π+π²)Remainder =1-(3-3π-π²)π

Step-by-step explanation:

Given (x³+3x²+3x+1)÷(x+π)

Division Method:

Quotient:x²+(3-π)x+(3-3π+π²)

x+π)x³+3x²+3x+1(

**** x³+πx²

__________________

*******(3-π)x²+3x

*******(3-π)x²+(3-π)πx

_________________________

********* (3-3π+π²)x+1

******(3-3π+π²)x+(3-3π+π²)π

______________________________

Remainder :1-(3-3π-π²)π

Therefore,

Dividend = (x³+3x²+3x+1)

Divisor = x + π

Quotient=x²+(3-π)x+(3-3π+π²)

Remainder =1-(3-3π-π²)π

•••♪

Answer 2

Step-by-step explanation:

hope it will help you..