Question

Find the remainder when3x^3- 4x^2+7x-5 is divided by (x -1)

Answer 1

Answer:

x-1=0,x=1

3(1)³-4(1)²+7(1)-5

3-4+7-5

-1+2

=1 is your answer

mark as a brainlist plz

Answer 2

Step-by-step explanation:

Let g(x)= x- 1

p(x)=3x^3- 4x^2+7x-5

now, g(x)=0

x - 1= 0

x= 1

Let,p(1) = 3(1)^3- 4(1)^2+7(1)-5

= 3 - 4 + 7 - 5

= 1+ 2

= 3 is your answer

" PLEASE MARK AS BRAINLIEST"