Question

Find the remainder when9x cube minus 3x square +x minus 5 is divided x minus 2/3

Answer 1

Answer:

-3 is the remainder

Step-by-step explanation:

x-2/3=0

x=2/3

Now, substitute x as 2/3.

p(x)=9x^3-3x^2+x-5

p(2/3)=9(2/3)^3-3(2/3)^2+2/3-5

=9(8/27)-3(4/9)+2/3-5

=8/3-4/3+2/3-5

=6/3-5

=2-5

=-3

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