Math, asked by karthikkavitha1977, 7 months ago

find the remainderf(x)=x3-6x2+2x-4 divide g(x)=3x-1

Answers

Answered by himmatbhavana
4

Answer:

f(x)=x^3-6x^2+2x-4 g(x)=3x-1=0

g(x)=3x=0+1,3x=1,x=1/3

(1/3)^3-6(1/3)^2+2(1/3)-4=1/27-6/9+ 2/3-4=-17+90/27=72/27=8/3

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