find the root of 16x - 10/x = 27
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Given 16x - 10/x = 27
⇒ (16x² - 10)/x = 27
⇒ 16x² - 10 = 27x
⇒ 16x² - 10 - 27x = 0
⇒ 16x² - 27x -10 = 0
⇒ 16x² - 32x + 5x - 10 = 0
⇒ 16x(x - 2) + 5(x - 2) = 0
⇒ (x - 2) (16x +5 ) =0
⇒ (x-2) = 0 or (16x + 5) = 0
⇒ x = 2 or 16x = -5
⇒ x = 2 or x = -5/16
∴ x = 2 , -5/16
⇒ (16x² - 10)/x = 27
⇒ 16x² - 10 = 27x
⇒ 16x² - 10 - 27x = 0
⇒ 16x² - 27x -10 = 0
⇒ 16x² - 32x + 5x - 10 = 0
⇒ 16x(x - 2) + 5(x - 2) = 0
⇒ (x - 2) (16x +5 ) =0
⇒ (x-2) = 0 or (16x + 5) = 0
⇒ x = 2 or 16x = -5
⇒ x = 2 or x = -5/16
∴ x = 2 , -5/16
yasummu:
please mark it as the brainliest
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Warning : This is not an answer but a message.
Hey dude sweetup who is asking this question. The answer given by dude Yasmmu is right and your book's answer is wrong. Check this pic yhat is Question no. 11 and its answer.
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