Question

find the root of quadratic equation 15x square -10 root6x+10

Answer 1

Answer:

Step-by-step explanation:

Answer 2

HEY Buddy.....!! here is ur answer

Given that : 15x²–10√6x+10

On comparing with ax²+bx+c

Here, a = 15, b = –10√6 and c = 10

According to Shridharacharya Formula :

$x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ = > x = \frac{10 \sqrt{6} \binom{ + }{ - } \sqrt{600 - 4 \times 15 \times 10} }{2 \times 15} \\ \\ = > x = \frac{10 \sqrt{6} }{30} \\ \\ = > x = \frac{ \sqrt{6} }{3} \\ \\ = > x = \frac{ \sqrt{3} \times \sqrt{2} }{ \sqrt{3} \times \sqrt{3} } \\ \\ = > x = \frac{ \sqrt{2} }{ \sqrt{3} }$

I hope it will be helpful for you....!!

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