In simplest radical form what are the solutions to the quadratic equation 6=x2-10x
Answers
Answer: The two solutions of the given quadratic equation are 5+sqrt31 and 5-sqrt31.
Step-by-step explanation:
The standard equation of quadratic equation is given by
ax^2+bx+c=0
x^2-10x-6=0 (given equation)
comparing the both equation, we get
a=1, b= -10, and c=-6
The two solution of quadratic equation is given by
x=( -b+sqrt(b^2-4ac))/2a and x=( -b-sqrt(b^2-4ac))/2a
plugging the value of a, b, and c, we get:
x1=(-(-10)+sqrt((-10)^2-4*1*(-6))/2*1 and x2=(-(-10)+sqrt((-10)^2-4*1*(-6))/2*1
x1=(10+sqrt124)/2 and x2=(10-sqrt124)/2
x1=5+sqrt31 and x2=5-sqrt31
Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34vSelect the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34vvvSelect the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34Select the correct answer.
What are the solutions of this quadratic equation?
x2 − 10x = -34v