Question

find the root of the following quadratic equation
$2x {}^{2} - x - \frac{1}{8} = 0$

Answer 1

16x²-8x-1=0
X=(-b±(b²-4ac))/2a
X=(8±64-64)/32
X=1/4

Answer 2

there are two values of x as solution. this is the formula required to find out the two values of a quadratic equation of the form-
$a {x}^{2} + bx + c = 0$
first value of x is
$x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}$
and second value of x is
$x = \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a}$
on evaluating, we get x=0.6, -0.1