Math, asked by saakshipiya6247, 1 year ago

Find the roots by completing the square 1 )root2x^2+7x+5root2

Answers

Answered by ayeshakhan12
6

 \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2} = 0 \\  {x}^{2}   +  \frac{7x}{ \sqrt{2} }  + \frac{5 \sqrt{2} }{ \sqrt{2} }  = 0 \\  {x}^{2}  +  \frac{7x}{ \sqrt{2} }  = -  5 \\  {x}^{2}  +  \frac{7x}{ \sqrt{2} }  +  { (\frac{7}{2 \sqrt{2} } })^{2}  = 5 +   ({ \frac{7}{2 \sqrt{2} } })^{2}  \\(  {x +  \frac{7}{2 \sqrt{2} } })^{2}  = 5 +  \frac{49}{8}  \\(  {x + \frac{7}{2 \sqrt{2} }  })^{2}  =  \frac{40 + 49}{8}  \\ x +  \frac{7}{2 \sqrt{2} }  =  \sqrt{ \frac{89}{8} }  \\ x =  \frac{ \sqrt{89} }{2 \sqrt{2} }  -  \frac{7}{2 \sqrt{2} }  \\ x  =  \frac{ \sqrt{89 } - 7 }{2 \sqrt{2} }   \\
Heyy friend your answer is here
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