Math, asked by vihang42, 10 months ago

find the roots of equation 21xsquare+17x-2​

Answers

Answered by ayushayushayushmaury
1

Step-by-step explanation:

21x^2+17x-2

21x^2+14x+3x-2

7x(3x+2)+1(3x+2)

(3x+2)(7x+1g

Answered by persianwolf221004
1

Answer:

21x^2+17x-2=0

comparing the given equation with ax^2+bx+c=0

a=21,b=17 and c=-2

by formula method,

x = -b+- √b^2-4ac/2a

= -17+-√289-168/42

= -17+- √ 121 / 42

= -17 +- 11 /42

x = 17 + 11 /42 OR x = 17-11/42

x= 28/42 OR x = 6/42

x = 2/3 or 1/7

2/3 or 1/7 are the roots of the given equation.

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