find the roots of equation 21xsquare+17x-2
Answers
Answered by
1
Step-by-step explanation:
21x^2+17x-2
21x^2+14x+3x-2
7x(3x+2)+1(3x+2)
(3x+2)(7x+1g
Answered by
1
Answer:
21x^2+17x-2=0
comparing the given equation with ax^2+bx+c=0
a=21,b=17 and c=-2
by formula method,
x = -b+- √b^2-4ac/2a
= -17+-√289-168/42
= -17+- √ 121 / 42
= -17 +- 11 /42
x = 17 + 11 /42 OR x = 17-11/42
x= 28/42 OR x = 6/42
x = 2/3 or 1/7
2/3 or 1/7 are the roots of the given equation.
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