Question

$\huge\mathfrak\red{QUESTION:-}$
Suzanne, Latisha, and Morgan measure their. Suzanne is 0.8 times the height of Latish, and Morgan is 1.09 times the height of Latisha. Who is the tallest? Use paper to draw to tape diagram to help you solve the problem and to explain your reasoning.​

Answer 1

Let ball A is thrown upward at t = 0. It takes time T to reach the ground. Ball B is dropped from the roof 1.00 s later. If both the balls reach the ground simultaneously, the flying time for ball B will be (T- 1) s.

The displacement of both the balls is (= -20 m).

Using y = + ut + (1/2)a initially for both balls are at = 20 and when both reaches ground where y = 0.

For ball A: 0 = 20 + + (1/2)(-10) ...(i)

For ball B: 0 = 20 + (1/2)(-10) ...(ii)

From Eqs. (i) and (ii),

= 5(2T - 1) ...(iii)

From Eqs. (i) and (iii), we get

- 2T - 3 = 0 (T + 1)(T - 3) = 0

T = 3s

From Eqs.(iii) = 25/3 m/s

Let ball A reaches maximum height at time t' after throwing. For ball A at maximum height, the velocity will be zero.

Using v = u + at

0 =(25/3) - 10 5/6 s

For maximum height reached by ball A,

Using

0 = - 2 x 10 x h'

h' = 125/36 m

Hence, maximum height reach by ball A

H = 20 + (125/36) = 845/36 m

Answer 2

Answer:

$\: \: \:$

Given:

Suzanne, Latisha, and Morgan measure their. Suzanne is 0.8 times the height of Latish, and Morgan is 1.09 times the height of Latisha.

To find:

Who is the tallest? Use paper to draw to tape diagram to help you solve the problem and to explain your reasoning.

Solution:

Consider the attached figure, while going through the following steps:

Let the height of Latisha be "x"

Suzanne is 0.8 times the height of Latish = 0.8 × x

Morgan is 1.09 times the height of Latisha = 1.09 × x

1.09 × x > x > 0.8 × x

If x = 1, we get,

1.09 × 1 > 1 > 0.8 × 1

1.09 > 1 > 0.8  

Morgan > Latisha > Suzanne

Morgan is the tallest.

Second tallest is Latisha

And the third tallest is Suzanne.

Therefore, the tallest is Morgan.