Question

Find the roots of quadratic equation x-3x-m(m+3)=0 where m is constant.

Answer 1

${x}^{2} - 3x - m(m + 3) = 0 \\ = > x = \frac{ - ( - 3) + | \sqrt{( { - 3}^{2} ) + - 4( - m(m + 3))(1)} | }{2(1)} \\ = > x = \frac{3 + \sqrt{4 {m}^{2} + 12m + 9 } }{2} \\ = > x = \frac{3 - \sqrt{4 {m}^{2} + 12m + 9 } }{2} \\ = > x = \frac{3 + (4m + 3)}{2} \\ = > x = \frac{3 - (4m + 3)}{2} \\ = > x = m + 3 \\ = > x = - m$
Hope it helps