Question

find the roots of quaratic equation x^2+7x+12=0​

Answer 1

Answer:

x^2+7x+12=0

x^2+3x+4x+12=0

x(x+3)+4(x+3)=0

x=-3 and -4

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Answer 2

Answer:

x²+7x+12

=> x² + 4x+3x +12

=>x(x+4)+3(x+4)

=>(x+3)(x+4)

Roots are (x+3) and (x+4)

Step-by-step explanation:

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