find the roots of the equation 8x^2+2x–3=0 and verify the answer
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p(x) = 8x^2 + 2x - 3 = 0
= 8x^2 +6x -4x - 3 = 0
= 2x(4x + 3) -1 (4x + 3) = 0
= (2x - 1) ( 4x + 3) = 0
= 2x - 1 = 0 = 4x +3 = 0
= x = 1/2 = x = -3/4
p(1/2) = 8*1/4 + 2*1/2 -3
= 2+1-3
= 3-3
= 0
p(-3/4) = 8*9/16 + 2 (-3/4) -3
= 9-6-3 / 2
= 0/2
= 0
= 8x^2 +6x -4x - 3 = 0
= 2x(4x + 3) -1 (4x + 3) = 0
= (2x - 1) ( 4x + 3) = 0
= 2x - 1 = 0 = 4x +3 = 0
= x = 1/2 = x = -3/4
p(1/2) = 8*1/4 + 2*1/2 -3
= 2+1-3
= 3-3
= 0
p(-3/4) = 8*9/16 + 2 (-3/4) -3
= 9-6-3 / 2
= 0/2
= 0
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