Question

Find the roots of the following quadratic (if they exist) by the method of completing the square.
√2x²-3x-2√2=0

Answer 1

Step-by-step explanation:

hope it helps you good evening

Answer 2

x = 4/√2  ;  x = -1/√2

Step-by-step explanation:

√2x² -3x -2√2 = 0

Dividing by √2, we get x² - (3/√2)x - 2 = 0

 x² - 2 * 1/2*(3/√2)x - 2 = 0

x² - 2 * 1/2*(3/2√2)x + (3/2√2)² - (3/2√2)² - 2 = 0

(x - 3/2√2)² = 9/8 + 2

(x - 3/2√2)² = 25/8

(x - 3/2√2) = +- 5/2√2  

Therefor x - 3/2√2 = +-5/2√2

Solving x - 3/2√2 = +5/2√2, we get x = 4/√2

Solving x - 3/2√2 = -5/2√2, we get x = -1/√2