Find the roots of the given equation : 2x-2/x=6 ; x ≠ 0
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let's follow this equation.
2(x-1)= 6x (after multiplying x on both side)
x-1 = 3x (after dividing 2 on both side)
-1 = 2x (after subtracting X on both side)
x = -1/2 (after dividing 2 on both side)
Answer is 19 while x ≠ 0
2(x-1)= 6x (after multiplying x on both side)
x-1 = 3x (after dividing 2 on both side)
-1 = 2x (after subtracting X on both side)
x = -1/2 (after dividing 2 on both side)
Answer is 19 while x ≠ 0
VijalPatel:
that's (2x-2)/x
sorry i noticed that later :p
happens :D
:)
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