Question

Find the roots of the polynomial by factorisation?​

Answer 1

Step-by-step explanation:

check this image.

here is your answer.

Answer 2

here is ur answer

ANSWER:-

$\bf 2x^2-x +\frac{1}{8} =0$

$\bf \frac {16x^2-8x+1}{8}=0 => 16x^2-8x+1=0$

now by middle term splitting

$16 {x}^{2} - 8x + 1 = 0$

$16 {x}^{2} - 4x - 4x + 1 = 0$

$4x(4x - 1) - 1(4x - 1) = 0$

${(4x -1)}^{2} = 0$

$x = \frac{1}{4} and \: \frac{1}{4}$

hope the answer helps

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