Math, asked by kittuprac1, 1 year ago

Find the roots of the quadratic equation √2x^+7x+5√2=0

Answers

Answered by Anonymous
11
Hey...

Here's your answer..

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 \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  \\ splitting \: the \: middle \: term \\  \\  \\  \sqrt{2}  {x}^{2}  + 5x + 2x + 5 \sqrt{2}  \\ x( \sqrt{2} x + 5) +  \sqrt{2} ( \sqrt{2} x + 5) \\  \\ thus \: factors \: are \: (x +  \sqrt{2} )and \: ( \sqrt{2} x + 5) \\  \\ roots \: are \:  -  \sqrt{2} and - 5 \div  \sqrt{2}
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HOPE IT HELPS

@Rêyaañ11
Answered by shumi76
7

your answer is -√2 and -5√2/2
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