Math, asked by BrainlyHelper, 1 year ago

Find the roots of the quadratic equation √2x²+7x+5√2=0.

Answers

Answered by nikitasingh79
11

SOLUTION :  

Given : √2x² + 7x + 5√2 = 0

√2x² + 5x + 2x +  5√2 = 0

[ 5 × 2  = 10  & 5 + 2 = 7]

x(√2x + 5) + √2(√2x + 5) = 0

(√2x + 5) (x + √2) = 0

√2x + 5 = 0   or  x + √2 = 0  

√2x = -5  or  x = - √2

x =  - 5/√2  or  x =  - √2

Hence, the roots of the quadratic equation √2x² + 7x + 5√2 = 0 are   - 5/√2  &  - √2.

★★ METHOD TO FIND SOLUTION OF a quadratic equation by FACTORIZATION METHOD :  

We first write the given quadratic polynomial as product of two linear factors by splitting the middle term and then equate each factor to zero to get desired roots of given quadratic equation.

HOPE THIS ANSWER WILL HELP YOU….

Answered by BrainlyVirat
7

Find the roots of the quadratic equation √2x²+7x+5√2=0.

Solution :

Comparing the given equation with ax^2 + bx + c = 0

We get,

a = √2

b = 7

c = 5√2

b^2 - 4ac = 7^2 - 4 × √2 × 5√2

= 49 - 40

= 9

Using Formula method,

x = ( -b +- √{ b^2 - 4 ac } / 2a )

x = (-7 +- √9) / 2 × √2

x = (-7 +- 3) / 2√2

x = -7-3 / 2√2 or x = -7+3/2√2

x = -10/2√2 or x = -4/2√2

x = -5/√2

or

x = -2/√2

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