Question

find the roots of x square + 4 x + 5 = 0​

Answer 1

Step-by-step explanation:

✔

${x }^{2} + 4x + - 5 = 0 \\ {x}^{2} + 5x - x - 5 = 0 \\ x(x + 5) - (x + 5) = 0 \\ (x - 1)(x + 5) = 0 \\ x = 1 \: or \: x = - 5$

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Answer 2

x^2+4x+5=0

it is in the form of a x^2+ bx+c=0

a=1,b=4,c=5

X= -b+_√b^2-4ac

2a

X= -4+_√(4)^2-4(1)(5)

2(1)

X= -4+_√16-20

2

x= -4+_√-4

2

this equation has no real roots

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