Question

Find the roots :
$2 {x}^{2} + 6 \sqrt{3} - 60 = 0$

Answer 1

2x^2+6√3x-60=0

2x^2+10√3x-4√3x-60=0

2x(x+5√3)-4√3(x+5√3)=0

x=-5√3       x=2√3