find the second onder derivative of function x^3 logx
Answers
Answered by
0
Answer:
x(6logx +5)
Step-by-step explanation:
First derivative = 3x^2logx + x^3*1/x
= 3x^2logx + x^2
Second dervative = 6x logx + 3x^2*1/x + 2x
= 6x logx + 3x + 2x
= 6x logx + 5x
= x(6logx +5)
Similar questions