Question

Find the second term and the nth term of an A.P. whose 6th term is

12 and the 8th term is 22. Also find sum of first 22 terms . Or In an a.p 3
15 , 27 ,... Which term is 120 less than its 93rd term.


help me to solve this question..

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Answer 1

Given, a₆=a+5d=12--------(1)

And a₈=a+7d=22----------(2)

Eq(2)-Eq(1)⇒2d=10

⇒d=10/2

⇒d=5

Substituting d=5 in(1),

a+5(5)=12

⇒a=12-25

⇒a=-13

Therefore, the second term of the AP,a₂=a+d=(-13)+5=-8

And nth term of the AP=a+(n-1)d

=(-13)+(n-1)5

=(-13)+5n-5

=5n-18

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Answer 2

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Refer the attachment for step by step explanation.