Question

Find the series of the quadratic polynomial 3x2-75and verify the relationship between zeroes and the coefficient

Answer 1

Answer:

so first we will find the zeroes of this polynomial

Step-by-step explanation:

3x square-75=0

common

3(x square-25)=0

3 will go that side in divide

now,

x square-25=0

x square=+25

x=root 25=5

now we will take alpha as 5

and beta as -5

In poly.3x square+0-75=0

= ax square +bx+c=0

a=3, b=0, c=-75

now

alpha+beta= -b/a

-5+5= -0/3

0=0

alpha x beta=c/a

-5 x 5= -75/3

-25=-25

hence verified