Question

find the side of a square of area (16x^2-8x+1) square units

Answer 1

Area of square =Side^2
=>16x^2-8x+1=side^2
=>(4x)^2-2×4x×1+(1)^2=side^2
=>(4x-1)^2=side^2
《using identity (a-b)^2=a^2+b^2-2ab》

=>Removing squares from both sides
=>4x-1=side of the square.

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Answer 2

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Given:-the side of a square of area (16x^2-8x+1)

We know that Formula

(a-b)²=a²-2ab+b²

Now,

Suggest this Equation as per as QUESTION:-

Equation:-16x²-8x+1

4²x²-2(4)(1)x+1²=(4x-1)²

here,

(4x-1)²=0

4x-1=√0

4x-1=0

So,

Side =4x-1



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