Question

Find the simple interest of the following:
Principal -₹1200
Rate -15%
Time: 8April to 20june



Kindly solve this...............

Answer 1

I think but I am not sure

1200/15%

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=36\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 73\: days} \\ \\ : \implies \text{Principal(p) = 1200\:rupees} \\ \\ : \implies \text{Rate(r) = 15\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{1200 \times 15\times\frac{73} {365} }{100} \\ \\ : \implies S.I = \frac{12\times 1095 }{365} \\ \\ \green{ : \implies \text{S.I= 36\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =36\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$