Question

find the simple interest on rs.14600 from 12th feb,2008 to 30th december,2008 at the rate of 5%p.a.Also find the amount ​

Answer 1

$\textbf{\huge{ANSWER:}}$

$\sf{Given:}$

S.I. ( Simple interest ) = Rs. 14600

Time = 12th Feb - 30th Dec ( 2008 )

=》 323 days

In years = $\frac{323}{365}$ years

Rate of Interest = 5% per annum

The formula is:

S.I. = $\frac{PRT}{100}$

Where, S.I. = Simple Interest

P = Principle

R = Rate of Interest

T = Time

Applying the formula:

S.I. = $\frac{14600\times5\times323}{100\times365}$

=》 $\frac{64600}{100}$

=》 $\boxed{\tt{S.I. = Rs. 646}}$

Amount = Simple Interest + Principle

Amount = 646 + 14600

$\boxed{\tt{Amount = Rs. 15246}}$

We just need to start from gathering the information from the question, set it up together, and then at last, you just need to solve it further.

Answer 2

\textbf{\huge{ANSWER:}}ANSWER:

\sf{Given:}Given:

S.I. ( Simple interest ) = Rs. 14600

Time = 12th Feb - 30th Dec ( 2008 )

=》 323 days

In years = \begin{lgathered}\frac{323}{365}\\\end{lgathered}

365

323

years

Rate of Interest = 5% per annum

The formula is:

S.I. = \begin{lgathered}\frac{PRT}{100}\\\end{lgathered}

100

PRT

Where, S.I. = Simple Interest

P = Principle

R = Rate of Interest

T = Time

Applying the formula:

S.I. = \begin{lgathered}\frac{14600\times5\times323}{100\times365}\\\end{lgathered}

100×365

14600×5×323

=》 \begin{lgathered}\frac{64600}{100}\\\end{lgathered}

100

64600

=》 \boxed{\tt{S.I. = Rs. 646}}

S.I.=Rs.646

Amount = Simple Interest + Principle

Amount = 646 + 14600

\boxed{\tt{Amount = Rs. 15246}}

Amount=Rs.15246

We just need to start from gathering the information from the question, set it up together, and then at last, you just need to solve it further.