Find the smallest 4-digit number which is divisible by 6, 8, 9 a. 2012 b. 2160 c. 2088 d. 2016
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Answered by
2
Answer:
b.2160
Simple just divide 2160 by 6,8,9 and 2160 is a 4 digit number divisible by all 6,8,9
Answered by
1
Answer:
smallest 4 digit no is d) 2016
Step-by-step explanation:
2012 ÷ 6 = 335.3333
2012÷ 8 = 251.5
2012÷ 9 = 223.5555
hence non of the no.s are not divisible by 2012
2160 ÷ 6 = 360
2160 ÷ 8 = 270
2160 ÷ 9 = 240
hence 2160 is divisible by all the no.s
2088 ÷ 6 = 348
2088÷ 8 = 261
2088 ÷ 9 = 232
hence 2088 is divisible by all the no.s
2016 ÷ 6 = 336
2016 ÷ 8 = 252
2016÷ 9 = 224
hence 2016 is divisible by all the no.s
2160 > 2088 > 2016
therefore 2016 is the smallest and is divisible by all the no.s
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