Question

Find the smallest 4-digit number which is divisible by 6, 8, 9 a. 2012 b. 2160 c. 2088 d. 2016

Answer 1

Answer:

b.2160

Simple just divide 2160 by 6,8,9 and 2160 is a 4 digit number divisible by all 6,8,9

Answer 2

Answer:

smallest 4 digit no is d) 2016

Step-by-step explanation:

2012 ÷ 6 = 335.3333

2012÷ 8 = 251.5

2012÷ 9 = 223.5555

hence non of the no.s are not divisible by 2012

2160 ÷ 6 = 360

2160 ÷ 8 = 270

2160 ÷ 9 = 240

hence 2160 is divisible by all the no.s

2088 ÷ 6 = 348

2088÷ 8 = 261

2088 ÷ 9 = 232

hence 2088 is divisible by all the no.s

2016 ÷ 6 = 336

2016 ÷ 8 = 252

2016÷ 9 = 224

hence 2016 is divisible by all the no.s

2160 > 2088 > 2016

therefore 2016 is the smallest and is divisible by all the no.s

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