find the smallest number by which 243 must be multiplied to obtain a perfect cube?
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3
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Ek no lo use karke deko ho jaye ga
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Prime factors of 243 = 3×3×3×3×3
Here 3 does not appear in 3's group.
3|243
3|81
3|27
3|9
3|3
|1
Therefore, 243 must be multiplied by 3 to make it a perfect cube.
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