Math, asked by Mubashshira6021, 1 year ago

Swati married 6 years ago . Her son was born 3 years after marriage. Presently she is 9/7 times of her married age . Find ratio of her son age after 10 years to her age at the time of marriage.

Answers

Answered by purbitanath
5

Answer:

21 :13

Step-by-step explanation:

let, at the time of marriage Swati's age was = x

now her age is = x + 6

atq,   x + 6 = 9/7 * x

or,    7x + 42 = 9x

or,    2x = 42

or,    x = 21

atq, her son was born 3 yrs after her marriage

∴ her son was born (6-3) = 3 yrs ago

son's present age = 3

after 10 yrs his age will be 3+10 = 13

∴ the required ratio = 21 : 13

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