Question

find the smallest number by which 2560 must be multiplied so that the product is a perfect cube​

Answer 1

Answer:

find out ..... first we have to take out its factors of 2560

Step-by-step explanation:

its factor are 2 *2*2*2*2*2*2*2*2*5

so here...2 has formed three pairs

but 5 doesn't

so 5*5 =25...

will be answer

Answer 2

Answer:

25

Step-by-step explanation:

Prime Factorisation of 2560:

2560 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 5

$> > \sqrt[3]{2560}$

$> > \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5}$

$> > 2 \times 2 \times 2\sqrt[3]{5}$

Therefore, 5 x 5 ,ie, 25 multiplied to make it into nearest perfect cube.

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