Find the smallest number
by which 2560 must be multiplied so that the product is a perfect cube
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prime factorisation of 2560=2×2×2×2×2×2×2×2×2×5
require no.=5×5=25
product=2560×25
=64000
√64000=2×2×2×5=40
√64000=40 ans
require no.=5×5=25
product=2560×25
=64000
√64000=2×2×2×5=40
√64000=40 ans
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