Find the smallest number of 6 digits which when divided by 25, 35, 42, 50 and 60 leaves 1 as remainder in each case.
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Answer:
Step-by-step explanation:
For this first find the LCM of the given numbers.
25 = 5²
35 = 5×7
42 = 2×3×7
50 = 2×5²
60 = 2²×3×5
LCM = 2100
Ans- 2100+1=2101
2101 when divided by 25, 35, 42, 50, 60 leaves remainder as 1.
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