Find the smallest number which when divided by 25, 40 and 60
leaves the remainder 7 in each case.
Answers
Answered by
1
Answer:
607
Step-by-step explanation:
Take out the LCM of the three number
Then add 7 to the LCM and you will get the answer
607
Answered by
1
LCM of 25,45,60=600
Now add 7 to the result=600+7
=607
Now add 7 to the result=600+7
=607
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