Find the smallest square number that is divisible by each of the numbers 8, 9 and 10.
Answers
Answered by
6
L.C.M. of 8,9,10 is 2*2*2*3*3*5=360
Since 2 and 5 are not in pairs multiply by 2 and 5 to make it a perfect square.
The required number=360*2*5=3600
The smallest square number divisible by 8,9,10=3600.
Similar questions
English,
1 month ago
Physics,
1 month ago
CBSE BOARD X,
2 months ago
Hindi,
9 months ago
Biology,
9 months ago