Question

Find the smallest square number which is divisible by each of the number 9,6,15.

Answer 1

HEYA MATE,

HERE IS UR ANSWER.

Thanks for asking this question.


Since, we wanted smallest perfect square number divisible by 6, 9 and 15.
So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.
Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).
= 90 × 2 × 5
= 90 × 10
= 900

Hence,
Required smallest square no. that's divisible by 6, 9 and 15 = 900

I HOPE IT HELPS U.