Question

Find the square of:
(i) x + 3y​

Answer 1

★Answer★

Find Here :-

• Square of (x +3y ) .

Using identity :-

• (a+b)² = (a²+2ab+b²).

So,

=> (x+3y)² = (x)² + 2× (x)×(3y) + (3y)²

=> (x+3y)² = (x²+6xy+9y²).

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★Some Important Identity ★

• (a-b)² =(a²+2ab+b²)

• (a²-b²)=(a+b)(a-b)

• (a+b)³=(a³+b³+3a²b+3ab²)

• (a-b)³=(a³-b³-3a²b+3ab²)

• (a+b+c)²=(a²+b²+c²+2ab+2bc+2ca)

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Answer 2

$\bf{ \huge{ \boxed{ \tt{ \red{Answer \: }}}}}$

$\bf \large{ \underline{ \bf{given}}}$

• $(a+ {b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

• $\star \: (x+ {3y})^{2}$

• $= {x}^{2} + 2 \times x \times 3y + (3 {y})^{2}$

• $= {X}^{2} + 6xy + 9 {y}^{2}$

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$<marquee>$

I hope it's help uh