Question

find the square root of (x² + 3x + 7 ) ( x² + 5x + 3) +( x- 2)²

plz don't spam and give the answer with explanation​

Answer 1

Answer:

$\underline\bold\red{♡hy \:mate♡}$

$\huge\underline\bold \red {♡AnswEr♡}</p><p>$

Given 22x +8+1 = 32. 2x => 28.22x +1 = 32. 2x

=> 256. (2x)² -32. 2x +1 = 0

Putting 2x = t, we get, 256 t² -32t +1 = 0

=> t = [-(-32) + (- 32)² -4 (256)(1)]/[2 (256)] = (32 ± 0)/512 = 1/16, 1/16

But t = 2x. Hence 2x = t = 1, 1 = 2-4, 2-4

=> x = -4, -4

Hence the solution of the given equation is x = -4

follow me to get follow back

Answer 2

Step-by-step explanation:

Given 22x +8+1 = 32. 2x => 28.22x +1 = 32. 2x

=> 256. (2x)² -32. 2x +1 = 0

Putting 2x = t, we get, 256 t² -32t +1 = 0

=> t = [-(-32) + (- 32)² -4 (256)(1)]/[2 (256)] = (32 ± 0)/512 = 1/16, 1/16

But t = 2x. Hence 2x = t = 1, 1 = 2-4, 2-4

=> x = -4, -4

Hence the solution of the given equation is x = -4

please follow me and Mark me the brainiest.