find the sum of -20 and 21 from the sum of -208 and -40.
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Answered by
3
Answer:
Given: a
2
=8 and a
4
=14 and n=21
We know that,
a
2
=a+d=8...(i)
and a
4
=a+3d=14...(ii)
Solving the linear equations (i) and (ii), we get
a+d−a−3d=8−14
⇒−2d=−6
⇒d=3
Putting the value of d in equation.(i), we get
a+3=8
⇒a=8−3=5
Now, we have to find the sum of the first 21 terms.
S
n
=
2
n
[2a+(n−1)d]
⇒S
21
=
2
21
[2×5+(21−1)(3)]
⇒S
21
=
2
21
[10+20×(3)]
⇒S
21
=21[5+10×(3)]
⇒S
21
=21[35]
⇒S
21
=735
Step-by-step explanation:
I hope my answer is correct
Answered by
0
Answer:
735
Step-by-step explanation:
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