find the sum of -3,1,5.....to17terms
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given series is -3,1,5,.........17 terms
s(n)=n/2(2a+(n-1)d)
=17/2(2*-3+(17-1)4)
=493
s(n)=n/2(2a+(n-1)d)
=17/2(2*-3+(17-1)4)
=493
shashank12:
tq it is correct answer
ur welcome
d=4how??
d means difference it is second number - first no: or third no:- second no: so here 1-(-3) =1+3=4 or 5-1=4
ok understood tq
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a=-3,n=17,d=1-(-3)=4
S₁₇=n/2[2a+(n-1)d]
S₁₇=17/2[2(-3)+(17-1)4]
S₁₇=17/2(-6+64)
S₁₇=17/2(58)
S₁₇=17(29)
S₁₇=493
S₁₇=n/2[2a+(n-1)d]
S₁₇=17/2[2(-3)+(17-1)4]
S₁₇=17/2(-6+64)
S₁₇=17/2(58)
S₁₇=17(29)
S₁₇=493
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