Question

find the sum of all 3 digit no. when divided by 12 leaves remainder 5.​

Answer 1

XYZ

Step-by-step explanation:

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Answer 2

Answer:

the smallest 3 digit number = 100 is divided by 5 103 is the 1st 3digit no which will give remainder 3

the largest 3 digit no=999

999/5 gives reminder.4=998will remainder 3

this series is obviously in AP,(103,108,111,....,998)

998=103+(n-1)5

n=895/5+1=180

so sum

n/12(first term +last term)

180/2(103+998)=90(1101)=99090