find the sum of all natural number between 500 and 1000 which are divisible by 13.
please solve this question very urgent
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Answered by
11
Let's find the first number divisible by 13 in the natural numbers between 500 and 1000.
500/13=38, remainder =6
38×13=494
494+13=507 is the first in the series.
a=507
we have, d=13
last number is 1000/13=78,remainder 12
last term =78×13=988
from eq for nth term of ap
988=507+(n-1)×13
481=13n-13
13n=494
n=38
sum=38/2 (507+988)
=28405
500/13=38, remainder =6
38×13=494
494+13=507 is the first in the series.
a=507
we have, d=13
last number is 1000/13=78,remainder 12
last term =78×13=988
from eq for nth term of ap
988=507+(n-1)×13
481=13n-13
13n=494
n=38
sum=38/2 (507+988)
=28405
Answered by
0
Answer:
28405
Step-by-step explanation:
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