Question

Find the sum of all the prime numbers between 10 and 20 and check whether that sum is divisible by all the single digit numbers

Answer 1

All the prime numbers between 10 and 20 are 11, 13, 17 and 19.
Their sum = 11+13+17+19 = 60
$divisibility \: by \: 1$

Every number is divisible by 1, so, 60 is divisible by 60.

$divisibility \: by \: 2$

We know that if the last digit of a number is 0, 2,4,6 or 8 , then the given number is divisible by 2. Here, the last digit is 0, so, 60 is divided by 2.


$divisibility \: by \: 3$
A number will be divided by 3 if the sum of all its digits is divisible by 3. Here, 6+0=6, which is exactly divisible by 3. Therefore, 60 is divisible by 3.


$divisibility \: by \: 4$
A given number will be divided by 4 if its last two digits are exactly divided by 4. 60/4=15.
So, 60 is divided by 4.


$divisibility \: by \: 5$
If the last digit of a number is either 0 or 5, then it is divisible by 5. Here, the last digit is 0. So, 60 is divided by 5.


$divisibility \: by \: 6$
If a number is divided by both 2 and 3 then it will exactly be divided by 6. Since 60 os divided by both 2 & 3 , therefore, 60 is divided by 6.


$divisibility \: by \: 7$
Take the last digit of the given number, double it and then subtract it from the rest of the digits in the original number . If the resultant is either 0 or any multiple of 7, then the given number is divisible by 7.
6- 0*2 =6, which is not divisible by 7. So , 60 is not divisible by 7.


$divisibility \: by \: 8$
60/8= 15/2.
So, 60 is not divisible by 8.


$divisibility \: by \: 9$
If the sum of all the digits of a number is divisible by 9 then the given number will be divided by 9.
Here, 6+0=6, which is not divisible by 9.
So, 60 is not divisible by 9.




ANS: The sum of all the prime numbers between 10 and 20 is 60. This dum is divisible by the single digits 1, 2, 3, 4, 5 and 6.





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Answer 2

Answer:

The sum is 60 and it is divisible by 1,2,3,4,5,6,

Step-by-step explanation:

we have to find the sum of all the prime numbers between 10 and 20 and also we have to check that sum is divisible by all the single digit numbers

All prime numbers between 10 and 20 are 11, 13, 17 and 19.

Sum = 11+13+17+19 = 60

Every number is divisible by 1, so, 60 is divisible by 60.

We know that if the last digit of a number is even , then the given number is divisible by 2. Here, the last digit is 0, therefore 60 is divisible by 2.

A number will be divided by 3 if the sum of all its digits is divisible by 3. Here, 6+0=6, which is exactly divisible by 3. Therefore, 60 is divisible by 3.

A given number will be divided by 4 if its last two digits are exactly divided by 4. So, 60 is divisible by 4.

If the last digit of a number is either 0 or 5, then it is divisible by 5. Here, the last digit is 0. So, 60 is divisible by 5.

If a number is divided by both 2 and 3 then it will exactly be divided by 6. Since 60 is divisible by both 2 & 3 , therefore, 60 is divisible by 6.

Take the last digit of the given number, double it and then subtract it from the rest of the digits in the original number . If the resultant is either 0 or any multiple of 7, then the given number is divisible by 7.

$6- 0\times 2 =6$, which is not divisible by 7.

So , 60 is not divisible by 7.

60 is not divisible by 8.

If the sum of all the digits of a number is divisible by 9 then the given number will be divided by 9.

Here, 6+0=6, which is not divisible by 9.

So, 60 is not divisible by 9.

ANS: The sum of all the prime numbers between 10 and 20 is 60. This dum is divisible by the single digits 1, 2, 3, 4, 5 and 6.

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