Question

find the sum of all two digit natural number which are divisible by 4

Answer 1

4, 8, 12.... 96
a = 4
d = 4
an = 96
a + (n-1) (4)= 96
n = (92/4) + 1
n = 24
Sn = (n/2)(2a + (n-1) d)
= (24/2)(8 + 23 × 4)
= 12 × 100
= 1200

Answer 2

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d = 4

a = 12

an = 96

an = a+(n-1)d

96 = 12+ 4n-4

96 -8 =4n 

n = 22

then ,

Sn = n/2 (a+an)

Sn = 11 (12+96)

Sn = 11 x 108

Sn = 1188

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