Question

find the sum of arithmetic progression :-

(1-1/n),(1-2/n),(1-3/n),............up to n terms.​

Answer 1

hope this helps uh.......

Answer 2

Answer:

Ap:(1 -1/n),(1- 2/n),(1 -3/n),...

a=(1-1/n)

d=1 -2/n -1 +1/n = -1/n

Sn=n/2(2a+(n-1)d)

=n/2(2 -2/n +(n-1)-1/n)

=n/2 (2 -2/n -1 +1/n)

=n/2 (1 -1/n)

=(n-1)/2

Hpe it hlps u :)

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