Question

find the sum of first 100 even natural number which are divisible by 5

Answer 1

here's your answer
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Answer 2

Answer:

The sum of first 100 even natural number which are divisible by 5 is 50500.

Step-by-step explanation:

To find : The sum of first 100 even natural number which are divisible by 5?

Solution :

The given question form an Arithmetic series.

Where, first term is a=10

Common difference is d=10    

Number of terms is n=100

The sum formula is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$S_n=\frac{100}{2}[2(10)+(100-1)(10)]$

$S_n=50[20+(99)(10)]$

$S_n=50[20+990]$

$S_n=50[1010]$

$S_n=50500$

Therefore, The sum of first 100 even natural number which are divisible by 5 is 50500.