Question

find the sum of first 100 odd notural number​

Answer 1

Step-by-step explanation:

1+3+5+6+7+9+ .... 100 terms.

Applying sum of A.P.

a = 1 , d = 2 , n = 100

n/2 × (2a + (n-1)d)

=100/2 × (2×1 + (100-1)2 )

= 50 × ( 200)

= 10000

Answer 2

Answer:

1000

Step-by-step explanation:

terms of the given series form an AP with first term a=1 and common difference d=2.

Therefore,

Sn=2n [2a+(n−1)d]

⇒Sn = 2n [2×1+(n−1)×2]

⇒Sn =2n [2+2n−2]

⇒Sn=n²

Sn=100×100=10000

i did it by calculating sum of n terms nd then putting value to it!!

hope it helps uh!