Question

find the sum of first 11 terms of the AP 2, 6, 10, 14​

Answer 1

Here's the Solution :

Given , the AP = 2,6,10,14

Here ,

first term , a = 2

common difference , d = 4

Now , Sum Up to 11th term :

= 11/2 {2a + (11-1)d}

= 11/2 { 2×2 + 10×4}

= 11/2 {4 + 40}

= (11/2 )×44

= 11×22

= 242

Happy learning

Answer 2

Answer:

A11=a+(n-1)d

A11=2+(n-1)4

A11=2+(14-1)4 (n=last term of ap)

A11=2+13(4)

A11=2+52

A11=54